Chemistry. How Do I Work Out The Percentage Abundance Of An Element?
Chemistry. The Question I Have Been Given Is: Thallium Has Two Naturally Occuring Isotopes, Thallium-203 And Thallium- 205. Its Relative Atimic Mass
Chemistry : How Do I Work Out The Percentage Abundance Of An Element
the question i have been given is: Thallium has two naturally occuring isotopes, thallium-203 and thallium- 205. Its relative atimic mass is Detirmine the percentage abundance of the lighter element. I dont want the answer, I would just like to know how to work out the answer so that I can answer similar questions int he fututre. ~~~ Delta-fan ~~~
Best Answer To Chemistry Question
Keep in mind: Since there are only two isotopes, the two percentages must add up to 100%. Also, when doing math problems, don't use percentages, use the decimal equivalent (.45 instead of 45%). You can represent the abundance of Tl-203 with x and the abundance of Tl-205 with (1-x). Then, solve this equation: 203(x) + 205(1-x) = x (converted to a percentage) will be your answer.
All Answers To Chemistry Questions
Answer 1Let the lighter isotope fractional abundance be L. Then we would have 203 L + 205 (1-L) = . But this calculation is only approximate, as the nominal masses of the isotopes differ slightly from the actual masses of and , respectively. Use the exact masses, along with the exact atomic weight of to get the correct answer of %.
Answer 2Relative molecular mass = [(True atomic mass of Isotope 1)*(Abundance of Isotope 1)+(True atomic mass of Isotope 2)*(Abundance of Isotope 2)] / 100 You can calculate the true atomic masses by accounting for all the protons, neutrons and electrons. Then with a little bit of algebra determine the abundance of both isotopes in your Thallium sample.
Answer 3Keep in mind: Since there are only two isotopes, the two percentages must add up to 100%. Also, when doing math problems, don't use percentages, use the decimal equivalent (.45 instead of 45%). You can represent the abundance of Tl-203 with x and the abundance of Tl-205 with (1-x). Then, solve this equation: 203(x) + 205(1-x) = x (converted to a percentage) will be your answer.
Answer 4These always come down to a fairly simple algebra problem: (Mass 1) * (%abundance of mass 1) + (mass 2) * %(abundance of mass 2) = atomic mass; So in your case (203) * (% of 1) + (205) * (% of 2) = or 203*x + 205*y = But we have x and y, two unknowns with 1 equation only.... but if we know that x and y are the only two (natural) isotopes of thallium then we have a second equation (% of isotope 1) + (% of isotope 2) = 100%; x + y = 100%; or y = 100%-x; So going back to the original problem 203*x + 205*y = y becomes (100% - x; or 1-x) 203*x + 205*(1-x) = , which is solvable. For a real trick, try finding it for an element with three isotopes assuming you know the % abundance of one isotope, the masses of all three, the relative atomic mass.
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