Chemistry. How Many Liters Of Seawater Would Have To Be Processed To Recover 1 Kg Of Gold?
Chemistry. A Cubic Meter Of Ocean Water Has 6 X 10^-6 G Gold. If The Total Mass Of The Water In Earth's Oceans Is 4 X 10^20kg, How Many Kilograms Of G
Chemistry : How Many Liters Of Seawater Would Have To Be Processed To Recover 1 Kg Of Gold
A cubic meter of ocean water has 6 x 10^-6 g gold. If the total mass of the water in Earth's oceans is 4 x 10^20kg, how many kilograms of gold are distributed throughout the oceans? Assume that the density of seawater is 1g/cm3. How many liters of seawater would have to be processed to recover 1 kg of gold. There's two questions to this problem. I would like to know how you would sove this problem and what's the answer? ~~~ sw33t_lil_azn08 ~~~
Best Answer To Chemistry Question
To get kg of gold, first, you convert your density in g/cc to Kg/m^3 which is 1000 kg/m^3. But since total mass of the water in Earth's oceans is 4 x 10^20kg, you can get the the volume of the water in the oceans. 4 x 10^20kg/1000 kg/m^3 = 4 x 10^17 m^3. But one cubic meter of ocean water has 6 x 10^-6 g gold, so 4 x 10^17 m^3 x (6 x 10^-6 g gold/m^3) = 24 x 10^11 g of gold or converting to kilograms = 24 x 10^8 Kg. To get the number of liters, use 6 x 10^-6 g gold/ m^3 or convert to 6x10^-9 kg/m^3. and use the following conversion factors, 1 liter = 1000 cc or cm^3 m = 100 cm, m^3 = 10^6 cm^3, you should get x 10^11(!!! ) Liters just to recover 1 kg of gold!!! So you see, nobody is applying to mine the oceans for gold.
All Answers To Chemistry Questions
Answer 1To get kg of gold, first, you convert your density in g/cc to Kg/m^3 which is 1000 kg/m^3. But since total mass of the water in Earth's oceans is 4 x 10^20kg, you can get the the volume of the water in the oceans. 4 x 10^20kg/1000 kg/m^3 = 4 x 10^17 m^3. But one cubic meter of ocean water has 6 x 10^-6 g gold, so 4 x 10^17 m^3 x (6 x 10^-6 g gold/m^3) = 24 x 10^11 g of gold or converting to kilograms = 24 x 10^8 Kg. To get the number of liters, use 6 x 10^-6 g gold/ m^3 or convert to 6x10^-9 kg/m^3. and use the following conversion factors, 1 liter = 1000 cc or cm^3 m = 100 cm, m^3 = 10^6 cm^3, you should get x 10^11(!!! ) Liters just to recover 1 kg of gold!!! So you see, nobody is applying to mine the oceans for gold.
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